The NCERT Solutions for Class 10 Maths Chapter 9, Some Applications of Trigonometry, provide students with a comprehensive guide to solving real-world problems using trigonometric concepts. This chapter primarily focuses on the practical uses of trigonometry, including determining heights and distances in various situations without directly measuring them. Students learn how to apply trigonometric ratios such as sine, cosine, and tangent to calculate angles and lengths in right-angled triangles. The chapter covers examples like finding the height of a tower, distance of a point from an observer, and the angle of elevation or depression of an object. With step-by-step explanations, these solutions help students gain a clear understanding of trigonometry’s applications in daily life, aiding their preparation for exams and improving problem-solving skills.
We try to teach you all Questions in easy way. We solve all chapter wise sums of maths textbook. In every chapter include NCERT solutions. For solutions of Exercise 9.1 click on Tabs :
Question 2.
A tree breaks due to storm and the broken part bends so that the top of the tree touches the ground making an angle 30° with it. The distance between the foot of the tree to the point where the top touches the ground is 8 m. Find the height of the tree.
Solution:
Using given instructions, draw a figure. Let AC be the broken part of the tree. Angle C = 30°
BC = 8 m
To Find: Height of the tree, which is AB
Total height of the tree is the sum of AB and AC i.e. AB+AC
In right ΔABC,
Using Cosine and tangent angles,
cos 30° = BC/AC
We know that, cos 30° = √3/2
√3/2 = 8/AC
AC = 16/√3 …(1)
Also,
tan 30° = AB/BC
1/√3 = AB/8
AB = 8/√3 ….(2)
Therefore, total height of the tree = AB + AC = 16/√3 + 8/√3 = 24/√3 = 8√3 m.
Height of the kite from the ground, BC = 60 m
AC = Inclined length of the string from the ground and
A is the point where string of the kite is tied.
To Find: Length of the string from the ground i.e. the value of AC
From the above figure,
sin 60° = BC/AC
⇒ √3/2 = 60/AC
⇒ AC = 40√3 m
Thus, the length of the string from the ground is 40√3 m.